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7r^2-42=7r
We move all terms to the left:
7r^2-42-(7r)=0
a = 7; b = -7; c = -42;
Δ = b2-4ac
Δ = -72-4·7·(-42)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-35}{2*7}=\frac{-28}{14} =-2 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+35}{2*7}=\frac{42}{14} =3 $
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